y^2+4y+21=5

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Solution for y^2+4y+21=5 equation:


Simplifying
y2 + 4y + 21 = 5

Reorder the terms:
21 + 4y + y2 = 5

Solving
21 + 4y + y2 = 5

Solving for variable 'y'.

Reorder the terms:
21 + -5 + 4y + y2 = 5 + -5

Combine like terms: 21 + -5 = 16
16 + 4y + y2 = 5 + -5

Combine like terms: 5 + -5 = 0
16 + 4y + y2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-16' to each side of the equation.
16 + 4y + -16 + y2 = 0 + -16

Reorder the terms:
16 + -16 + 4y + y2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 4y + y2 = 0 + -16
4y + y2 = 0 + -16

Combine like terms: 0 + -16 = -16
4y + y2 = -16

The y term is 4y.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4y + 4 + y2 = -16 + 4

Reorder the terms:
4 + 4y + y2 = -16 + 4

Combine like terms: -16 + 4 = -12
4 + 4y + y2 = -12

Factor a perfect square on the left side:
(y + 2)(y + 2) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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